Unformatted text preview: potential energy is U A = 10 J. Thus the kinetic energy is E = K + U K (x = 3.5) = E – U ⇒ A = 19 – 10 = 9.00 J The definition of kinetic energy yields K = (1/2)mv 2 v = √(2K/m) = 6.71 m/s ⇒ b) What is the position of the turning point on the right side? The particle turns around when its kinetic energy is zero. The kinetic energy is zero when the potential energy equals the mechanical energy. The potential energy function between x = 7 m and x = 8 m is given by U = [(U D – 0) /(76)] × (x7) = 27(x7) The function takes the value of E = 19 J at 19 = 27(x7) x = 19/27 + 7 = 7.70 m ⇒ c) What is the position of the turning point on the left side? The potential energy function between x = 1 m and x = 3 m is expressed as U = [(U A U C )/(31)]×(x1) + U C U = 6(x  1) + 22 ⇒ The function takes the value of E = 19 J at 19 = 6(x1) + 22 x = (19  22)/( 6) +1 = 1.50 m ⇒...
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 Fall '08
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 Physics, Energy, Kinetic Energy, Potential Energy, Work, 1 m, 2k, Tomoyuki Nakayama

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