This preview shows page 1. Sign up to view the full content.
Unformatted text preview: equation at the starting point and at the end of the ramp, we get E i = E f mgH = (1/2)mv 2 v = (2gH) = 24.2 m/s b) What is the maximum height h of his/her jump above the end of the ramp? The vertical component of the launching velocity is v 0y = vsin = 10.2 m/s At the peak of the jump, the vertical component of the velocity is zero. The kinematic equation which relates the velocity of a projectile to its displacement yields v y 2  v 0y 2 = 2gy 2 v 0y 2 = 2gh h = v 0y 2 / 2g = 5.33 m c) If s/he increased his/her weight by putting on a backpack, would h then be greater, less or the same? The launching velocity does not depend on the weight of the skier, and the projectile motion does not depend on the mass of a projectile. Therefore, h is the same....
View Full
Document
 Fall '08
 Field
 Physics, Work

Click to edit the document details