Unformatted text preview: potential energy is zero. Thus the kinetic energy is E = K + U K (x = 6.5 m) = E  0= = 35.0 J ⇒ The definition of kinetic energy yields K = (1/2)mv 2 v = √(2K/m) = 11.8 m/s ⇒ b) What is the position of the turning point on the right side? The particle turns around when its kinetic energy is zero. The kinetic energy is zero when the potential energy equals the mechanical energy. The potential energy function between x = 7 m and x = 8 m is given by U = [(U D – 0) /(76)] × (x7) = 50(x7) The function takes the value of E = 35 J at 35 = 50(x7) x = 35/50 + 7 = 7.70 m ⇒ c) What is the position of the turning point on the left side? The potential energy function between x = 1 m and x = 3 m is expressed as U = [(U A U C )/(31)]×(x1) + U C U = 11(x  1) + 42 ⇒ The function takes the value of E = 35 J at 35 = 11(x1) + 42 x = (35  42)/( 11) +1 = 1.64 m ⇒...
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This note was uploaded on 01/15/2012 for the course PHY 2048 taught by Professor Field during the Fall '08 term at University of Florida.
 Fall '08
 Field
 Physics, Work

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