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Unformatted text preview: tension force from the wire and the gravitational force. Applying the translational equilibrium condition along the x and y axes, we get R x  Tcos = 0 R y + Tcos W = 0 Choosing our rotational axis at the hinge, the rotational equilibrium condition yieldsW(L/2)sin(2) + TLsin = 0 Note that the angle between the beam and y axis is 2, for this is the exterior angle opposite the two vertices of angle and . b) Find the tension in the wire. Solving the balance of torques equation in part a), we get T = Wsin(2) /(2sin) = 300 sin50 / (2sin25) = 272 N c) Find the horizontal and vertical components of the force of the hinge on the beam. We solve the balance of forces equations in part a), we get R x = Tsin = 272 sin25 = 115 N R y = WTcos = 300  272cos25 = 53.5 N...
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This note was uploaded on 01/15/2012 for the course PHY 2048 taught by Professor Field during the Fall '08 term at University of Florida.
 Fall '08
 Field
 Physics, Work

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