Unformatted text preview: tension force from the wire and the gravitational force. Applying the translational equilibrium condition along the x and y axes, we get R x  Tcosθ = 0 R y + Tcosθ – W = 0 Choosing our rotational axis at the hinge, the rotational equilibrium condition yieldsW(L/2)sin(2θ) + TLsinθ = 0 Note that the angle between the beam and –y axis is 2θ, for this is the exterior angle opposite the two vertices of angle θ and θ. b) Find the tension in the wire. Solving the balance of torques equation in part a), we get T = Wsin(2θ) /(2sinθ) = 300 × sin50º / (2sin25º) = 272 N c) Find the horizontal and vertical components of the force of the hinge on the beam. We solve the balance of forces equations in part a), we get R x = Tsinθ = 272 × sin25º = 115 N R y = WTcosθ = 300  272cos25º = 53.5 N...
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 Fall '08
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 Physics, Force, Work, Ry, translational equilibrium, rotational equilibrium condition, Tomoyuki Nakayama

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