This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Math 201 Fall 2011 Assignment #2 Solutions October 1, 2011 • Grade problems 1 and 2, 10 marks each, 20 total for this assignment. 1. y = 1 /t + u , so, y = 1 t 2 + u = 1 t 2 1 t ( 1 t + u ) + ( 1 t + u ) 2 = 1 t 2 + u t + u 2 Thus, the equation for u is u = u/t + u 2 , which is a Bernoulli equation. Let w = 1 /u , w = u u 2 = u/t + u 2 u 2 = 1 t w 1 this is a linear equation, i.e., w + w/t = 1 . The integrating factor is μ ( t ) = e ´ (1 /t ) dt = e ln t = t Multiply μ ( t ) on both sides, ( μw ) = μw + μw t = μ = t Integrate on both sides, μw = tw = t 2 / 2 + C , isolate w , w = t 2 + C t . Now substitute in u , u = 1 w = 1 t/ 2 + C/t = 2 t t 2 + C 1 where C 1 = 2 C . So, y = 1 t + u = 1 t + 2 t t 2 + C 1 1 2. The right hand side f ( x,y ) = y x (1 + ln y ln x ) = y x 1 1 + ln( y/x ) To check the homogeneity, f ( kx,ky ) = ky kx 1 1 + ln ky kx = y x 1 1 + ln( y/x ) = f ( x,y ) so the rand hide side is homogeneous to degree 0. To solve it, let u = y/x , i.e.,i....
View
Full
Document
This note was uploaded on 01/15/2012 for the course MATH 201 taught by Professor Steacy during the Winter '10 term at University of Victoria.
 Winter '10
 STEACY
 Math

Click to edit the document details