Quiz4Soln - 1 GHz = 10 9 Hz 2.7*500*10^8(1/10^9 = 1.35 2(4...

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CDA3101 Quiz 4 Last Name ____________________ Fall 2010 First Name ____________________ 1. (6 points) Suppose a program (running on a MIPS processor) has the following distribution of instruction types. 10% Floating point CPI = 2 20% Integer CPI = 1 20% Load/Store CPI = 4 50% Branches CPI = 3 (a) What is the average CPI for this program? 10%*2 +20%*1+20%*4+50*3 = 2.7 (b) If this program had 500 million instructions and ran on a 1GHz computer, how long would it take ( in seconds
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Unformatted text preview: )? 1 GHz = 10 9 Hz. 2.7*500*10^8*(1/10^9) = 1.35 2. (4 points) Suppose we enhance a computer to make all floating-point instructions run five times faster. If the execution time of some benchmark before the floating-point enhancement is 10 seconds , what will the execution time of the same benchmark after the floating-point enhancement be, if 75% of the 10 seconds is spent executing floating-point instructions? 75%*10 / 5 + 10-75%*10 = 1.5+2.5 = 4s...
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This note was uploaded on 01/15/2012 for the course CDA 3101 taught by Professor Small during the Summer '08 term at University of Florida.

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