AIR_STRIPPING_SOLUTION - ENV 6015 GAS STRIPPING HOMEWORK...

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ENV 6015 GAS STRIPPING HOMEWORK SOLUTIONS Solution 1: O H e O H e H SO O H SO 2 2 2 4 2 2 3 2 4 4 4 4 2 2 2 + + + + + + + + 3 4 2 2 3 2 2 SO O SO 4 2 3 4 3 4 2 2 2 4 2 167 . 0 96 1 32 1 1 mgSO mgO mgSO molSO molO mgO molSO molO = × × s mgO s sol mgCOD mgO COD L mg utilized O 2 2 2 5800 4 . 0 60 350 = × × = Flow (l/s) Rate SO 4 3- × 0.167 3 4 2 mgSO mgO Rate O 2 (mg O 2 /L-min) 540 2.9 0.48 1080 6.1 1.02 2160 14.4 2.40 4320 34.9 5.82 Flow = 540 L/s Flow = 1080 L/s Flow = 2160 L/s 0 26 26 26 1 28.9 32.1 40.4 2 31.9 38.3 54.8 3 34.8 44.4 69.2 4 37.7 50.5 83.5 5 40.6 56.6 97.9 7 46.5 68.9 126.7 10 55.3 87.3 169.9 Flow(L/s) Mass flow (mg/min.) 540 6.70E+05 1080 1.41E+06 2160 3.32E+06 4320 8.05E+06 1
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Mass Flow Vs Flow 0.00E+00 1.00E+06 2.00E+06 3.00E+06 4.00E+06 5.00E+06 6.00E+06 7.00E+06 8.00E+06 9.00E+06 0 1000 2000 3000 4000 5000 Flow(L/s) Mass Flowmg(mg/min.) ( t s l C C a K MO = 2 ) ) ( t s l C C MO a K = 2 C l mg s / 4 . 7 = C 0 = t Flow MO 2 K l a 540 0.48 0.065 min. -1 1080 1.02 0.138 min. -1 2160 2.40 0.324 min. -1 4320 5.82 0.786 min. -1 Volume = 4m × 20 2 = 1600m 3 = 1.6 × 10 6 L Mass flow = mv () t s l C C a VK = Flow mv 540(l/s) 1.6 ×10 6 L () . min / 10 67 . 0 / 1 / 4 . 7 . min 065 . 0 6 mg l mg l mg × = 1080(l/s) 1.41 ×10 6 mg/min. 2160(l/s) 3.32 ×10 6 mg/min. 4320(l/s) 8.05 ×10 6 mg/min. 2
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L mg mg s s mg 6 10 348 . 0 . min . 34800 . min 60 5800 × = = × need 300L/s from graph SOLUTION 2 D = 1 ft L 1 = 0.467 gpm G = 23.81 hr ft H = 515 G = 23.81 3 3 ft L 32 . 28 L mol 4 . 22 1 hr ft × × = 30.1 hr mol L 1 = 0.467 1336 . 0 min gal × hr min 60 mol g 18 L g 1000 ft L 32 . 28 gal ft 3 3 × × × = 5894 hr mol L 2 = 0.633 1336 . 0 min gal × 7983 hr min 60 mol g 18 L g 1000 ft L 32 . 28 gal ft 3 3 = × × × hr mol L 3 = 0.7 1336 . 0 min
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AIR_STRIPPING_SOLUTION - ENV 6015 GAS STRIPPING HOMEWORK...

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