problem02_59 solution

University Physics with Modern Physics with Mastering Physics (11th Edition)

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2.59: (a) Denote the time for the acceleration (4.0 s) as t 1 and the time spent running at constant speed (5.1 s) as t 2 . The constant speed is then at 1 , where a is the unknown acceleration. The total l is then given in terms of a , t 1 and t 2 by , 2 1 2 1 2 1 t at at l + = and solving for a gives . s m 5 . 3 s) s)(5.1 0 . 4 ( ) s 0 . 4 )( 2 1 ( m) 100 ( )
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Unformatted text preview: 2 1 ( 2 2 2 1 2 1 = + = + = t t t l a (b) During the 5.1 s interval, the runner is not accelerating, so a = 0. (c) . s m 54 . 1 ) s 1 . 9 ( ] s) 4 )( s m 5 . 3 [( 2 2 = = t v (d) The runner was moving at constant velocity for the last 5.1 s....
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