per3.Oct.2011.chapter 4 review p 3 final

# per3.Oct.2011.chapter 4 review p 3 final - Chapter 4 Review...

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Unformatted text preview: Chapter 4 Review Polynomial Equations & Inequalities To solve a polynomial equation there are several strategies, you can Ø use the factor theorem Ø factor by grouping Ø solve graphically using TOV, transformations or a graphing calculator 4.1 Solving Polynomial Equations Using factor theorem Equation f(x) = x3 + x2 - 4x - 4 Possible factors: ±1, ±2, ±4 f(1)= (1)3 + (1)2 – 4(1) – 4 = 1+1-4-4 = -6 f(-1)= (-1)3 +(-1)2 - 4- 4 = -1+1+4-4 So (x+1) is a factor = 0-1 1 1 -4 -4 -1 0 4 1 0 -4 0 = R 0 =x2 -4 0 = (x-2)(x+2) So the solution is f(x)= (x-2)(x+2)(x+1) Ø Factor by grouping f(x)= x3 + x2 - 4x - 4 = x2 (x+1) -4 (x+1) = (x2 -4) (x+1) = (x + 2)(x-2)(x+1) Ø Graphically...
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## This note was uploaded on 01/14/2012 for the course MAT 107 taught by Professor Sda during the Spring '11 term at Beacon FL.

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per3.Oct.2011.chapter 4 review p 3 final - Chapter 4 Review...

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