Lecture13

Lecture13 - Lecture 13 10/26/11 Background reading: Berg,...

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Lecture 13 10/26/11 Assignment: Segel: page 205: Problems 1, 2, 4 and 5 Background reading: Berg, et al: pages 427 – 435 Garrett and Grisham: pages 65 - 71 Outline: Biochemical standard state Coupled reactions Energy-rich compounds Factors contributing to greater stability of products than reactants of hydrolysis of energy-rich compounds Bond strain Stabilization of product by ionization Stabilization of product by isomerization More resonance forms of products than reactants
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In the last lecture we had found that: The G of a reaction is dependent on the equilibrium constant and on the displacement from equilibrium. G = - 1364 log K eq + 1364 log [B] [A] G o is the Standard change in free energy. G o = -1364 log K eq G = G o + 1364 log [B] [A] Biochemical standard state Since many reactions that occur in biological systems have a H + as a substrate or product, biochemists have modified the definition of the standard state to the Biochemical Standard State. Biochemical Standard State = G o / Under this definition, all reactants and products except H + are considered to be 1 M. The H + concentration is 10 - 7 M. G = G o / for reactions with no H + . G is not equal to G o / for reactions with H + .
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Tables of G o/ are valuable in comparing various reactions and determining whether they will be endergonic or exergonic under particular conditions. (Table VIII on Page 412 of the Segel book demonstrates such a table and will be useful to you as you work the problems in today’s assignment.) Coupled reactions
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Lecture13 - Lecture 13 10/26/11 Background reading: Berg,...

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