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Unformatted text preview: l,‘ I mianahg FHK'JA are 110+ H9 [14 Abs
3 x The Law Of Sine’s Gnu; Coiled DEW/me JrE‘fm’lahg L "IM‘QﬁijL WU.“ have MA 0Q) vhoo Giant} 0004 W
' '7 OMqu 0004th . (a) M anglas are acme ([3) TM acme angies and 0&8 obtuge angle (7—0 golve GU“. 01311“?in Abk I. means .40 "Ffﬂd _H’\Q Q I .Hq Eb HS 8 [deg rnfl & ‘ .. . I  ‘ *Hls (aw/BJLQS . CASE 1: One Side and two angles are known (ASA 01“ 3AA).
CASE 2: Two Sidé‘ﬁ and the angle opposite one of them are known (SSA). f MLLYQ mam}; CASE 3: Two sides and the included angle are known (SAS). 3;“le : gﬁ
CASE 4: Three sides are known (SSS). a lo
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H 5th _ _S{nP> _, sum: S . OK 13 C Case 3:8AS W————=Q am Km”; b
P\ + FbI C: 1 [‘80 1. Solve SAA or ASA Triangles LAND) pmwa ab: 3:) gm K, p134}; £530 .
_A=37°, CC=75°,a=11 ‘ Lo H $337+???)
' B: 6%° . _ . ' 3I'n68 R C B b: ems2L)
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anB n $1°ﬁC~ )3 d" c. : Sin C
115 36’ No Triangle It" a 11 = [9 sin A‘ then
side a is not sufficiently long to [mm a
triangkr. Figure .14. Figure 14
a «i h 2 bsinA T 51 hr: {min}: Two Triangles If h =19 sin A < a. and
a < 59 two distinct triangles can be
One RightTliangle [fa = h z 531“ A formed from the. given information. See
then side a is just long enough "to form a Figure '16.
right trianglé. See Figure 1.5. . Figure 16
FlgureTS bsinA < aanda < b
a= h =bsinA _
a h=bsinA Dnns.I Triangle Ifrz I). only one trian—
gle can he formed. See Figure [7. Figure 17
a a b 3. Solve Applied Problems To measure the height of a mountain, at surveyor takes two sightingg of the peak at a
distance 900 meters apart on a direct line to the 1‘11t')unt‘z~1imm See. Figure 31(1‘1).
The first observation results in an angle of elevation of 47“ and the second results in
an angle of elevation of 35“. If the transit is 2 meters high. what the height h of the
nmuntain‘? ...
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 Fall '11
 BlisinHestiyas

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