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8.2 - l,‘ I mianahg FHK'JA are 110 H9[14 Abs 3 x The Law...

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Unformatted text preview: l,‘ I mianahg FHK'JA are 110+ H9 [14 Abs 3 x The Law Of Sine’s Gnu; Coiled DEW/me Jr-E‘fm’lahg L "IM‘QfiijL WU.“ have MA 0Q) vhoo Giant} 0004 W ' '7 OMqu 0004th . (a) M anglas are acme ([3) TM acme angies and 0&8 obtuge angle (7—0 golve GU“. 01311“?in Abk I. means .40 "Fffld _H’\Q Q I .Hq Eb HS 8 [deg rnfl & ‘ .. . I - ‘ *Hls (aw/BJLQS . CASE 1: One Side and two angles are known (ASA 01“ 3AA). CASE 2: Two Sidé‘fi and the angle- opposite one of them are known (SSA). f MLLYQ mam}; CASE 3: Two sides and the included angle are known (SAS). 3;“le : gfi CASE 4: Three sides are known (SSS). a lo 3.23:: : 9‘“ )9 C 3.923.- : ' CL c:- Case 1 : ASA Case T: SM (POR CASQI Gmd CQxS‘E-Lrj Na will LL$e LQijD ‘— stage. (For Caseg Camel CogQL’L we will (Age Lam/Q ‘05; Casings (Sec-[(00 (853;) GEES“ Cage 45 Lhw OF Swag . 7:0?“ Q 4H9}an LUHF Sfch G/ )3,C 61773 I _. OPPoSHQ Cantata?) A, R, C VQ'SIDQC'JI'V91EJ / H 5th _ _S{nP> _, sum: S . OK 13 C Case 3:8AS W————=Q am Km”; b P\ + Fb-I- C: 1 [‘80 1. Solve SAA or ASA Triangles LAND) pmwa ab: 3:) gm K, p134}; £530 . _A=37°, CC=75°,a=11 ‘ Lo H $337+???) ' B: 6%° . _ . ' 3I'n68 R C B b: ems-2L) 3.1.9 : 5% 2 19%: ‘32} gram; 5mA 52de H X T a r T <5 (—0732— : f a I] (L: H $03} »‘/t—/—1-1\. [7:15, (3:25, B=63° anB n $1°fiC~ )3 d" c. : Sin C 115 36’ No Triangle It" a 11 = [9 sin A‘ then side a is not sufficiently long to [mm a triangkr. Figure .14. Figure 14 a «i h 2 bsinA T 51 hr: {min}: Two Triangles If h =19 sin A < a. and a < 59 two distinct triangles can be One RightTl-iangle [fa = h z 531“ A formed from the. given information. See then side a is just long enough "to form a Figure '16. right trianglé. See Figure 1.5. . Figure 16 FlgureTS bsinA < aanda < b a= h =bsinA _ a h=bsinA Dnns.I Triangle Ifrz I). only one trian— gle can he formed. See Figure [7. Figure 17 a a b 3. Solve Applied Problems To measure the height of a mountain, at surveyor takes two sightingg of the peak at a distance 900 meters apart on a direct line to the 1‘11t')unt‘z~1imm See. Figure 31(1‘1). The first observation results in an angle of elevation of 47“ and the second results in an angle of elevation of 35“. If the transit is 2 meters high. what the height h of the nmuntain‘? ...
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