FA2011lecture14

FA2011lecture14 - 0.25 x 0.25 x 0.25 x 0.25 x 0.25 x 0.25 x...

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To get statistically significant results, have to pool data from multiple pedigrees (families) Data is analyzed by calculating a LOD (logarithm of odds) score for each pedigree Lod score = log 10 (probability of a certain degree of linkage/probability of independent assortment) Lod score > 3 (i.e. 1000-fold greater probability of linkage than of independent assortment) is accepted as sufficient evidence of linkage Lod scores <3 from multiple pedigrees can be added together to get a cumulative Lod score > 3
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D-M1 d-M2 D-M1 d-M2 d-M2 d-M2 D-M2 d-M2 d-M2 d-M2 D-M1 d-M2 d-M1 d-M2 d-M2 d-M2 NR R NR NR R NR 2 recombinants/6 potential recombinants so RF = 30% If unlinked p =
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Unformatted text preview: 0.25 x 0.25 x 0.25 x 0.25 x 0.25 x 0.25 x B If 20 cM apart, p = 0.4 x 0.1 x 0.4 x 0.4 x 0.1 x 0.4 x B If 30 cM apart, p = 0.35 x 0.15 x 0.35 x 0.35 x 0.15 x 0.35 x B If 40 cM apart, p = 0.3 x 0.2 x 0.3 x 0.3 x 0.2 x 0.3 x B p(linkage at 20cM) 0.00026 x B p(no linkage) 0.00024 x B log 10 Lod score for 20 cM = log 10 = p(linkage at 30cM) 0.00034 x B p(no linkage) 0.00024 x B Lod score for 30 cM = log 10 log 10 = = 0.15 Lod score for 40 cM = log 10 log 10 = = 0.12 p(linkage at 40cM) 0.00032 x B p(no linkage) 0.00024 x B Calculation of LOD scores 0.03 = DNA marker alleles 1,2 DNA marker allele 3 only alleles: 2,3 1,3 2,3 2,3 1,3 2,3 2,3...
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This note was uploaded on 01/16/2012 for the course BICD 100 taught by Professor Nehring during the Fall '08 term at UCSD.

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FA2011lecture14 - 0.25 x 0.25 x 0.25 x 0.25 x 0.25 x 0.25 x...

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