This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: 3.3: Homogeneous Equations with Constant Coefficients Remark Assume that y H x L = e r x is a solution to the n th order, linear, homogeneous differential equation a n y H n L + ” + a y = 0. Then, since d i dx i e rx = r i e rx , for 1 £ i £ n , we have a n r n e r x + a n 1 r n 1 e r x + ” + a e r x = if and only if a n r n + a n 1 r n 1 + ” + a = 0. Definition The characteristic equation for the n th order, linear, homogeneous differential equation a n y H n L + ” + a y = 0. is given by a n r n + a n 1 r n 1 + ” + a = 0. Theorem  Solutions to the n th Order, Linear, Homogeneous DE with Constant Coefficients: Distinct and Real If the roots r 1 , ..., r n of the characteristic equation are real and distinct, Then y H x L = c 1 e r 1 x + c 2 e r 2 x + ” + c n e r n x is a general solution to a n y H n L + ” + a y = 0. Example Solve the IVP y I 3 M + 2 y '' 5 y ' 6 y = 0, y H L = 1, y ' H L = 2, y '' H L = 3. Mathematica Example Solve the IVP y I 3 M + 2 y '' 5 y ' 6 y = 0, y H L = 1, y ' H L = 2, y '' H L = 3 using Mathematica . First, let's factor the characteristic equation... In[5]:= Factor @ r^3 + 2 r^2 5 r 6 D Out[5]= H 2 + r L H 1 + r L H 3 + r L Or we could just solve... In[6]:= Solve @ r^3 + 2 r^2 5 r 6 0, r D Out[6]= 88 r fi  3 < , 8 r fi  1 < , 8 r fi 2 << Hence, using our theory, we see that the general solution is given by...
View
Full
Document
This note was uploaded on 01/16/2012 for the course MATH 306 taught by Professor Keithemmert during the Fall '11 term at Tarleton.
 Fall '11
 KeithEmmert
 Equations

Click to edit the document details