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Unformatted text preview: 102 Fall 09 Class Notes Week of Oct 12 Revised Oct 13 u H t L = R Q L H t L + G Q H t L , t > v H t L = G Q H t L = ' Output' voltage Input Output Relation dv dt = G dQ dt = G u H t L R v H t L R dv dt + k v H t L = k u H t L d k dt k = 1 for k = d n v H t L dt n + 1 n 1 a k d k v H t L dt k = m b k d k u H t L dt k n th order differential equation. The coefficient of the hhighest degree is nonzero. Comes from EQUILIBRIUM LAWS OF SCIENCE EXAMPLE : d 2 v H t L dt 2 + a 1 d v H t L dt + a v H t L = d u H t L dt + b u H t L Printed by Mathematica for Students CIRCUIT EXAMPLE : L d 2 Q H t L dt 2 + R dQ H t L dt + G Q H t L = u H t L v H t L = G Q H t L Output volts u H t L Input Volts d 2 dt 2 Q H t L + R L d dt Q H t L + G L Q H t L = u H t L L d 2 dt 2 v H t L + R L d dt v H t L + G L v H t L = G L u H t L This is our IP OP RELATION ! HOW DO SOLVE FOR v H . L given u H . L ?? LAPLACE TRANSFORMS ** ** ** ** ** ** ** ** ** ** ** ** ** ** Recall v H t L = t W H t s L u H s L ds where W H t L is ' generalises' e kt , t > W H . L defined on the " positive Half line" Make the change of variable = t s d =  ds t W H t s L u H s L ds = W H L u H t L d CHANGE THE SUBJECT ... .. COMPLEX PLANE z = x + i y < x, y < RIGHT HALF PLANE Consists of all points z such that Re z > PICTURE HERE ON THE WHITE BOARD 2 Laplace.2.nb Printed by Mathematica for Students We prefer to use the letter s instead of z : Right HalfPlane = 8 s Re s < Specifying sigma specifies the half plane. Laplace Transform : of a function W H t L of time t defined on the HalfLine : t F H s L = Limit T T e st W H t L dt = e st W H t L dt Re s > is called the "Abcissa of Convergence" H Forget it ! L In Engineering we just calculate if the answer does not make sense We just throw it away ! HERE AND BELOW F H s L s in righthalf plane will denote a Laplace Transform : F H . L = L H W H . LL A function in the Time Domain becomes a function in the Laplace Domain viz a Right Half Plane. Example W H t L = e 4 t t = 4 For Res > 4, F H s L = Lim T e st e 4 t dt = Lim T e H s 4 L t H s 4 L = Lim 1 e H s 4 L T s 4 = 1 s 4 For s NOT EQUAL TO 4 Blows up if s = 4 ! s = 4 Re.s = 4 is the barrier ! W H t L = t k k t k = F H s L = Lim T e s t 1 ds = Lim I 1 e sT M 1 s 1 s with = Laplace.2.nb 3 Printed by Mathematica for Students Arbitrary k Positive Integer e st t k dt Recall d e st ds =  t e s t d n e st d n s = H t L n e st Hence e st t k dt = H 1 L k d k ds k e st dt = H 1 L k d k ds k 1 s k = 1 F H s L = 1 s 2 k = 2 F H s L = 2 s 3 k = 3 F H s L = 3.2 s 4 k F H s L = k ! s k + 1 How about NEGATIVE INTEGERS : W H t L = 1 t ??...
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This note was uploaded on 01/16/2012 for the course EE 102 taught by Professor Levan during the Spring '08 term at UCLA.
 Spring '08
 Levan
 Volt

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