Checkpoint 5.1 MAT 117

# Checkpoint 5.1 MAT 117 - a a a a a a = 2a-10 44 Geometry...

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Section 5.1 pp. 427-429 My answers are high lighted 18. 4 3 3 20 15 xy y x - - = y x 4 3 2 24. 35 5 28 4 - - x x = 5 ) 1 ( 4 - 36. 2 2 2 2 20 3 2 25 4 s rs r s r - + - = 20 25 4 2 2 2 - - - y y s r 50. Geometry. The volume of the box is represented by ) 6 5 ( 2 + + x x (x+5). Find the polynomial that represents the area of the bottom of the box. Section 5.2 pp. 434-436 (x+2) ) 6 5 ( 2 + + x x 18. 9 4 20 11 3 * 4 7 3 3 2 2 2 2 2 - - - + + - - x x x x x x x = 364 7 12 60 11 6 4 2 4 - + + + x x x x 34. p p p p p 2 9 3 9 18 6 2 + - ÷ - = p p p 2 9 2 2 + + 48. 3 2 2 * 3 5 2 8 6 * 4 3 7 14 2 2 2 2 2 - + + - + + + - + - x x x x x x x x x x x Was unable to figure out Section 5.3 pp. 441-442 16. cd cd 4 11 4 5 + = cd 4 24. 3 9 3 2 - - - x x x = x+3 36. 15 8 2 3 15 8

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Unformatted text preview: a a a a a a = 2a-10 44. Geometry. Find the perimeter of the given figure. 5 2 9-x x not so sure on this one Section 5.4 pp. 454-455 54. 4 2 3 10 5 2--+ w w = ) 2 ( 2 ) 2 ( 5--+ w w 58. 9 1 3 4 3 2 2--+ + x x x = 2/(x+3)(x+1) 62. 1 2 5 6 4 2 2-+ + + y y y y y 74. Geometry. Refer to the triangle in the figure. Find an expression that represents its perimeter....
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