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Unformatted text preview: D ) + ] = 130 the way to calculate is the same as in question 2. 1 5. If D has an exponential distribution with mean 7 then the pdf of D is given by f D ( x ) = 1 7 e1 7 x . As in the last 2 questions we need to nd E [min { D, 7 } ] and E [(7D ) + ]. E [min( D, 7)] = 7 * P ( D 7) + Z 7 s 7 es/ 7 ds = 7 e1 + (714 e1 ) 4 . 43 E [(7D ) + ] = Z 7 7s 7 es/ 7 ds = 7Z 7 s 7 es/ 7 ds = 7(77 e1 ) 2 . 575 E [Prot(7)] = 20 E [min { D, 7 } ]5 E [(7D ) + ] = 75 . 725 . 2...
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This note was uploaded on 01/16/2012 for the course ISYE 3232 taught by Professor Billings during the Spring '07 term at Georgia Institute of Technology.
 Spring '07
 Billings

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