C613SPRING08_PS2

C613SPRING08_PS2 - (in eV). Are these even or odd electron...

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Chemistry C613 Mass Spectrometry Spring 2008 Problem Set 2 Due Wednesday Jan. 23, 2008 (at the beginning of class). 1. IE C2H6 = 11.52 eV IE CH3 = 8.92 eV D 0 (CH 3 CH 2 -H) = 101.1 kcal/mol D 0 (CH 3 -CH 3 ) = 90.1 kcal/mol D 0 (C 2 H 5 +• H) = 33.65 kcal/mol Q1. Given the information above, calculate: A. The ionization energy for the ethyl radical (C 2 H 5 ) in eV B. D 0 (CH 3 +• CH 3 ) in kcal/mol C 2 H 6 PE ( eV ) r (10 -10 m) 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 CH 3 + CH 3 C 2 H 5 + H C 2 H 6 +
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Q2. Finish the potential energy diagrams above for dissociation products of C 2 H 6 +• . CH 3 + and C 2 H 5 + are products in the dissociations. Label all transitions and dissociation energies
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Unformatted text preview: (in eV). Are these even or odd electron ions? Q3. The experimentally derived IE (Appearance Energy) for C 2 H 6 was found to be 11.55 eV. Why the difference? Would this be considered an adiabatic transition? Q4. What experiments could you perform to determine apparent ionization energies of your molecule or possible fragmentation mechanism. Q5. What would the De Broglie wavelength be for an electron accelerated to 70eV and 7eV?...
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This note was uploaded on 01/18/2012 for the course C 613 taught by Professor Davide.clemmer during the Spring '08 term at Indiana.

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C613SPRING08_PS2 - (in eV). Are these even or odd electron...

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