Chemistry Mystery Solutions Write Up

Chemistry Mystery Solutions Write Up - compound, resulting...

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Drew Rasmussen Katri Truhler Chemistry 111L – 015 21 October 2010 Mystery Solutions Write Up A. Claims: To begin I knew that HCl and Na2CO3 reacted to form a fizzy bubbly liquid. I used this to narrow E and D down to HCl and Na2CO3. From there I narrowed AgNO3 down to B by using B + (Na2CO3) giving us a brown liquid. I knew B had to be AgNO3 because it was the only liquid that reacted with Na2CO3 to form a brown liquid. Once I knew B I was able to do the equation B + A knowing B and I used my table of known reactants to find A to be KI. From here I knew that the last chemical had to be Pb(NO3)2. I plugged these back in and tested to make sure they worked, and the reactions checked out. a. E is Na2CO3 b. D is HCl c. A is KI d. B is AgNO3 e. C is Pb(NO3)2 f. F is NaCl B. Reflection. a. This is not a good method of testing for Na+ and NO3- ions because Na+ and NO3- ions will react with one another to form NaNO3 which is a water soluble
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Unformatted text preview: compound, resulting in an aqueous solution of NaNO3. b. Trials with the same net ionic equation include: (Notebook pages: 29,31,32) b.i. Pb(NO3)2 + NaCl, and Pb(NO3)2 + HCl both had the same net ionic eqn. b.ii. The net ionic eqn was: Pb 2+ + 2Cl- PbCl2 b.iii. AgNO3 + HCl and AgNO3 + NaCl both had the same net ionic equation b.iv. The net ionic eqn was: Ag + + Cl- AgCl c. I would take the sinks and collect 100mL of water from both sink. Then I would add 100mL of KI to the water. If there is Pb 2+ present there will be a reaction where the liquid turns very yellow. The KI I would use would be about 1 molar. The more Pb 2+ ions there are the more PbI2 will form. So, the more precipitate you get, and the yellower the solution will tell you which sink has Pb 2+ in it....
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Chemistry Mystery Solutions Write Up - compound, resulting...

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