exam1solutions

exam1solutions - Math 2250 Exam #1 Solutions 1. What is the...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Math 2250 Exam #1 Solutions 1. What is the average rate of change of the function v ( t ) = csc( t ) over the interval [ / 6 ,/ 2]? Answer: The average rate of change of v ( t ) over [ / 6 ,/ 2] is simply v ( / 2)- v ( / 6) / 2- / 6 = csc( / 2)- csc( / 6) / 3 = 1 sin( / 2)- 1 sin( / 6) / 3 = 1 1- 1 1 / 2 / 3 = 1- 2 / 3 =- 1 / 3 =- 3 . 2. Determine either of the horizontal asymptotes to the curve y = 3 x- 5 2 4 x 2 + 6 x- 9 . Answer: Let f ( x ) = 3 x- 5 2 4 x 2 +6 x- 9 . The curve has a horizontal asymptote y = L if lim x + f ( x ) = L or lim x - f ( x ) = L . So that we dont have to worry about minus signs, lets evaluate the limit as x goes to + . To do so, we will multiply by 1 /x 1 /x (since the highest power of x is x 2 , but its under a square root so it only counts as degree 1): lim x + 3 x- 5 2 4 x 2 + 6 x- 9 = lim x + 3 x- 5 2 4 x 2 + 6 x- 9 1 /x 1 /x = lim x + 1 x ( 3 x- 5 2...
View Full Document

Page1 / 3

exam1solutions - Math 2250 Exam #1 Solutions 1. What is the...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online