f10exam1solutions - Math 113 Exam #1 Solutions 1. What are...

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Unformatted text preview: Math 113 Exam #1 Solutions 1. What are the domain and range of the function f ( x ) = e x x 4- 1 ? Answer: Notice that x 4- 1 is only defined when x 4- 1 is non-negative, meaning that x - 1 or x 1. Moreover, the function f is only defined when the denominator is non-zero, which excludes x = 1. Therefore, the domain of f is { x : x <- 1 or x > 1 } = (- ,- 1) (1 , + ) . As for the range, notice that both the numerator and the denominator are always positive, so negative numbers and zero are definitely not in the range. As x gets very negative, the numerator gets very close to zero. Also, as x gets close to- 1, the denominator gets very close to zero while the numerator goes to 1 /e > 0. Hence, the range of f consists of all positive numbers: Range( f ) = { y : 0 < y } = (0 , + ) . 2. Let f ( x ) = e 3 x- 2 . Is f invertible? Why or why not? If f is invertible, what is f- 1 ( x )? Answer: Yes, f is invertible. To see why, notice, first of all, that 3 x- 2 is an increasing function and passes the horizontal line test. Moreover, e x is also an increasing function that passes the horizontal line test. Hence, the composition f ( x ) = e 3 x- 2 is also an increasing function, so it has an inverse....
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This note was uploaded on 01/18/2012 for the course MATH 2250 taught by Professor Chestkofsky during the Fall '08 term at University of Georgia Athens.

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f10exam1solutions - Math 113 Exam #1 Solutions 1. What are...

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