Che+201_additional+problems - Chapter 2 2.6 : 4.3 *10 5...

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Unformatted text preview: Chapter 2 2.6 : 4.3 *10 5 miles 2.18: a) For A: R=0.7 °C, Xmean= 72.8 °C, s= 0.3 °C For B: R=5.8 °C, Xmean= 100.2 °C, s= 2.3 °C b) Thermocouple B exhibits a higher degree of scatter and is also more accurate. 2.23: The flow is turbulent 2.25: a) 200 crystals / min mm; 10 crystals / min*mm 2 b) 4.0 crystals/s c) r’ = 84.7 D’-108(D’) 2 2.27: a) V = 0.06102 exp (3600t) 2.32: a) y =2.11*10-3 R+4.50*10-4 b) 110 kg H2O/h 2.36: a) Slope = 1.573(dimensionless) b) C= e 12.736 Chapter 3 3.3. a) 35 kg b) 27 l/s c) 29 lbm/min d) 0.5 cm 3 3.12 a) r = 545.5ρ – 539.03 b) 4.6 kg Ile/h c) The valve of r and hence the Ile mass flow rate calculated in part (b) would be too high 3.15. a) 2526 kg/min b) 457 mol/s c) P of stream is the same as the density at 20 C and 1 atm. 3.16. a) 936 mol CH3OH b) 8715lbm/h 3.16. a) 500 g min b) 1.10 g mL c) 0.300 g CaCO g suspension Chapter 4 4.1: a) Continuous, transient b) 3.00 kg/s c) 333s 4.3: ) a m v = 59.7 kg/h, m 1 = 40.3kg/h b) The flow chart is identical to that of (a), except that mass flow rates (kg/h) are replaced by...
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This note was uploaded on 01/18/2012 for the course 155 201 taught by Professor Buettner during the Fall '08 term at Rutgers.

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Che+201_additional+problems - Chapter 2 2.6 : 4.3 *10 5...

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