AAE352_Summer_Lec08

AAE352_Summer_Lec08 - How to apply thermal loads EAa(DT) R1...

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June 23, 2010 AAE 352 Summer 2010 Andrew J. Ritchey aritchey@purdue.edu ARMS B144 765-494-5985 https://engineering.purdue.edu/AAE/Academics/Courses/aae352/2010/summer EA a(D T) EA a(D T) R 1 R 3 How to apply thermal loads 8-1
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How to calculate thermal loading in elements. AAE 352 Summer 2010 June 23, 2010 8-2
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(  (  T EA P L T L thermal D D D a AAE 352 Summer 2010 Equal and opposite forces (P thermal ) appear to develop at the element ends and act on the global model. “Equivalent” thermal force June 23, 2010 8-3
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L P E EA L D AAE 352 Summer 2010 (  L T L a D D Temperature increase causes elemental displacements. If these displacements are restricted then thermally induced forces result. L D L (  L T L a D  D L D L June 23, 2010 8-4
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(  thermal P EA T P a D   AAE 352 Summer 2010 L D L L P P How much force does it take to push the ends back to where they were before the element expanded due to temperature? (  0 Thermal mech PL L L T L D D D June 23, 2010 8-5
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(  thermal P EA T a D AAE 352 Summer 2010 L P thermal P thermal L P P The bottom line (  P T June 23, 2010 8-6
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AAE 352 Summer 2010 D T 1 2 3 June 23, 2010 8-7
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AAE 352 Summer 2010 F 21 F 22 EA a(D T) EA a(D T) The thermal force is a substitute for the heating effect It is not the same thing as the mechanical force on or
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AAE352_Summer_Lec08 - How to apply thermal loads EAa(DT) R1...

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