{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HW_Week01_Solution

# HW_Week01_Solution - 3000 lb 30 4000 lb 20 10 30 Problem...

This preview shows pages 1–9. Sign up to view the full content.

60˚ 34.641” R cy 3000 lb 30” 20” 4000 lb 10” 30” Problem 2-4: The structure shown in the figure is an idealization of an engine mount. Find the internal forces in the 5 two-force members. The supports on the right (at C and E) are pinned. B A C D E R cx R ey R ex x y

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
ΣM E =(4000)*(40)+(3000)*(90)-R cx (34.641)=0 R cx = 12,413 lb ΣF x =R cx +R ex =0 R ex =-12,413 lb Joint E: E 30˚ 12413 lb F ED B A C D E R cy R cx R ey R ex ΣF x =-12,413-F ED cos(30)=0 F ED =-14,338.3 lb ΣF y =R ey -F ED cos(60)=0 R ey =7166.67 lb R ey
4000 lb 3000 lb B A C D E R cy R cx = 12413 lb R ey = 7166.67 lb R ex = -12413 lb ΣF y =R cy +7166.67 -4000 -3000=0 R cy =-166.67 lb C 30˚ 12413 lb 166.67 lb Joint C: F CB F CD ΣF x =-F CB -F CD cos(30)+12413=0 F CB =12413-F CD cos(30) ΣF y =-166.67-F CD cos(60)=0 F CD =-333.33 lb F CB =12701.7 lb

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
ΣF x =-F CB -F CD cos(30)+12413=0 F CB =12413-F CD cos(30) ΣF y =-166.67-F CD cos(60)=0 F CD =-333.33 lb F CB =12701.7 lb Joint D: D 30˚ F DB F DA 30˚ 30˚ 333.33 lb ΣF x =-14333.3cos(30)-333.33-F DA cos(30)=0 F DA =-14666.7 lb ΣF y =-333.33sin(30)+(14333.3)sin(30)+F DB +F DA sin(30)=0 F DB =333.33 lb 14,333.3 lb
4000 lb 3000 lb B A C D R cy = 166.7 lb. R cx = 12413 lb 12,702 lb. (T) 333 lb. (C) Final results E R ey = 7166.67 lb R ex = 12,413 lb

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Problem 2-6: Solution A design team insists that a truss structure whose idealization is shown in Figure 2- 6 (b) is the best solution for a space system to be launched to Mars. The two idealizations shown in Problem Figure 2-6(b) and (c) and represent the math models of the two competing designs. Complete the following tasks.
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern