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Lecture-6

# Lecture-6 - AAE352 Lecture 6 Inertia forces with rotational...

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AAE 352 AAE352- Lecture 6 Inertia forces with rotational acceleration

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AAE 352 Rotational acceleration about the c.g. causes translational acceleration along the structure θ && r r θ && z n W
AAE 352 Rotational acceleration creates d’Alembert forces in addition to those computed using the load factor rotational acceleration inertia forces are added to the load factor effect θ && mr θ && z i n w z i n w z i n w z i n w

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AAE 352 Example-calculate weight due to rotational acceleration of two tip tanks located 220 inches on either side of the c.g. R=220 in. m=w/g I F mR θ = && R θ && 2 1.08 rad / sec θ = &&
AAE 352 Tip tank inertia loads tank weighs 2000 lb. R=220 in. m m=2000/g F I = (2000/g)*(220 in/12)*1.08 = 1230 lb. F I = 1230 lb. mR θ && θ & &

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AAE 352 Calculate the “applied” loads to find the shear force in the connectors for each tank if the aircraft load factor is n z = 1. 1230 lb. θ & & 1230 lb. 2000 lb. 2000 lb. n z = 1 +z
AAE 352 Right wing tank load FBD Load #1= n z *2000 lb. =1*2000 lb. Load #2 =1230 lb. V = 2000+1230 =3230 lb.

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AAE 352 Left wing tank load FBD Load = n z *2000 lb. =1*2000 lb. 1230 lb. V = 770 lb. =2000-1230
AAE 352 Rotational acceleration produces an inertia moment c.g. r dm dm r I 2 p = θ & & = p I Moments θ && p I θ &&

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AAE 352 Engineering units for I p I p ~ slug-ft 2 1 lb = 1 slug-ft/sec 2 1 slug = 1 lb-sec 2 /ft.
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Lecture-6 - AAE352 Lecture 6 Inertia forces with rotational...

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