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Shearstressreview

Shearstressreview - AAE352 Lecture 23 Formulas for shear...

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AAE 352 1 AAE352 Lecture 23 Formulas for shear stress and shear flow

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Why does the beam need shear stresses and shear forces? AAE 352 2
AAE 352 3 Objective- using a formula for shear stress distribution from AAE204 Restriction, at least one axis of symmetry area zz upper surface area i i i above cut cut V Q tI Q ydA y A y A τ = = = = i i i Q y A =

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AAE 352 4 Where do we want to find the shear stress and in what direction? Examples showing cuts and thicknesses cut zz cut VQ I t τ = ( 1 ) cut i i i Q ydA A shaded y = = =
AAE 352 5 Other examples notice also that the section must come apart into two pieces i zz i VQ I t τ =

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An example AAE 352 6 1,2 i i i i Q y A = =
A different cut AAE 352 27-7 1,2 i i i i Q y A = =

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A different cut AAE 352 27-8 1,2 i i i i Q y A = =
A different cut AAE 352 27-9 1 2 3 1,3 0 0 i i i i Q y A dA A dA = = = + - =

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AAE 352 10 Largest shear stresses final result NA V
A tricky one for the test Closed section but with symmetry Section is symmetrical about the vertical axis Why do I care?

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