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exam3key - I - 2’ [Zng-‘é’Z?05-’c7)cmfilz 61/11.,...

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Unformatted text preview: I - 2’ [Zng-‘é’Z?05-’c7)cmfilz 61/11., 6 i J- ‘- Z B: J- I‘HWH 3-0 0/0 m0 5 g c )/ N “75> J .5 L 2% x/DI/S" lam». y. Irégx/O’vg; . fl = /'6/ X/o'ZUZ 7, v ~47 “L J" 2' K : i, : 2-83x/0 125m : NJ x/o M /” fax/04713 ’20 —-/0 K: J /'76;</o m : #3 X/0 m LT=+I bio—71270529 -. - “'7va ' :"quzy‘c> T ‘ . I '7 > Vida/Mug a E 6:22»); Zqu'q'C I;3'7L"Zq62‘g ~ $17.7 I 535’5 2 q) C32§3 A. aaf7fiéfl¥ Q%%me/%db @4-MWJ{)€;1%%{K. Aft-H) M 22. (12 points) The infrared spectrum of 1H79Br shows the v=0 to v=l transition at 2650 Gin—1. a) Determine the Vibrational force constant for the HBr molecule. The atomic mass of 1H is 1.0078 amu and the atomic mass of 79Br is 78.918 amu. b) In-‘contrast to HBr the molecule 1H35C1 undergoes the VZO to v=1 transition at ~2885 amide If the atomic mass of 3501 is 34.9689, what is the Vibrational force constant for 11435013 0) What doesthis say about the interatomic potential of HBr as compared to HCl? ' 13 '" a) 70 '— 99: =. (3'0X/0’0CM/5){265'05m:,) :- 7'q55/0 5' a; = 3. =7 7/ a .L )5: (all? /‘ 0 2”" /“ Km) 2' 5 ‘ :m M : '0073 'j W (277%) ’2 ' fl flvg'mngri , a “27 _. iv (211.7t‘in/o’ .l'ésm d/m" #1 O'qfi'amvt . N lf+ __ 7 h : LH x 101,11, Weary/45:50 Z )3) m r» #65 X/o’ 13 . J} —-1 L) 70: B-gSX/O 9 fl c. W51) =. v77?5m~11~ I.w7g+3‘f'%3'l 5 ~17 ~ - [0 k . (536/ pa» / 62 X j] "Z? in €46: wag-)7? HZ. X/D A: ‘2. at? a 8 23. Five initially empty tanks are each filled with one of the following gases: N2, Ne, 02, CO, and He. The tanks are cooled until they reach a temperature of 1K. 3. As the tanks are cooled light is shined through each tank. At certain temperatures the light passing through a tank is scattered more indicating the formation of droplets of liquid. List the order in which the gases liquefy. b. Relate the order that the gases liquefy to the intermolecular forces you learned. Be as specific as possible do not simply list the intermolecular forces responsible. If the same intermolecular force is responsible in two cases explain why one gas liquefies before the other. 0. Suppose the London dispersion forces that are always present were suddenly magically turned off. What would you observe? {we a, Wat/cabin; T) ——————» [as a W Home 0‘) Co, ohm, Ni, Lu. T 715/ it iii/co :imw ow Miriam (a Z 0% Oh. lWx/Q- Landon olsfltm; 50 CO is. flat. y BOWL WOQAA 0% om’Q Oh Polafiwubtlilg. 1Q Polanéalétli‘i MW bolt» flag" Flu; NLhM l0? w, lort‘box bowl (€( 0L => 0?, 8.3,. I . __ ate-MIL @C’m 5;ka fora/(chmuj ' Mb i4. loan“, lTalplrL. imam/aw an 011* 39 fr VOA . Valarie—«L9 £535) 13 24 (l2pts) Xenon and fluorine will react to form binary compounds when a mixture of these two gases is heated to 400 °C in a nickel reaction vessel. A 100.0 mL nickel container is filled with xenon and fluorine giving partial pressures of 1.24 and 1.0.10 arm, respectively, at a temperature ef 25 DC. The reaction vessel is heated to 400 °C to cause a reaction to occu and then cooled to a temperature at which fluorine is a gas and the xenon fluoride is a nonvolatile solid. The remaining fluorine gas is transferred to a 50.0 mL nickel container where the pressure of F2 is 15.24 atm at 25 °C. Assuming all the xenon has reacted, what is the formula of the product? 14 25. (12pts) Leading scientists at IU have recently announced the development of a molecule that has been nicknamed the “Teflon gas.” Its special properties arise from the fact that, while it is a relatively large molecular weight molecule, it has extremely low intermolecular forces, with the smallest intermolecular force to molecular weight ratio of any molecule known. Because of your immense curiosity and the fact that no details of the compound have been released, you have stolen a sample contained in a locked, 0.500L stainless steel cylinder marked with the following information: boiling point: 10K; density at STP: 2.976g/L; colorless; freezing point: 1.5 K. A. Determine the molar mass of this unknown compound. use : RT“ M f” M W a (273K>(§-f-W> , ac. ' ..————...........,..-......»...._...u..m-_\..l ..........._..... u “M. "WWW—q... j 56+ (1A M l B. The following “real gas” law seems to apply well to this molecule, having a volume correction but no pressure correction. Explain how this law matches its physical properties, and ' explain what the constant k represents physically. P (V — nk) = nRT ' ' ' 9' ‘ “A a. 'LW-Ea fl 6§\[email protected]~Sesfpmdmdfmam’wvwwj EWK ‘fhe vwflsauhr [email protected]$ nflf flfjhfiidg No Preset/(:5? Cal‘fiE’Q-‘Htm Medal be W55” 19"“ EMF; ‘lfitm‘fi Messrs "no 55mg? wool y‘all/deer: in flw'fiw les 5,11 #33 Ml” ( (a) dds %u> r€&uc§A spend because of altnqcflhw? threes C. Draw a graph of PV/nRT versus Pressure from 0-500 atm showing the expected deviatiou from ideal behavior. Label both the x and y axes and give appropriate numbers. .3»! /‘ I . . . Z olex/ ah e ,3 I“ v I V K v _ i (75 l l in C) mark/é? (3’10 slim-abs mammal ) ...
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This note was uploaded on 01/17/2012 for the course S 117 taught by Professor Stephenjacobson during the Fall '11 term at Indiana.

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exam3key - I - 2’ [Zng-‘é’Z?05-’c7)cmfilz 61/11.,...

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