Lecture 12 - Fig. 12-6: We will reduce the network to its...

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Lecture 12 figures 1 Fig. 12-1: A simple load resistor attached to a non-ideal voltage source. We will determine the power delivered to a load resistor for various values of R L . Fig. 12-2: A simple load resistor R L attached to a non-ideal voltage source. We will determine the power delivered to a load resistor as a function of R L , and then optimize this power. Fig. 12-3: This optimization applies to a load resistor attached to a non-ideal current source as well. Fig. 12-4: A plot of the Power P L as a function of R L . The optimum power is delivered to the load resistor at R L = R s . This optimum power is P L = V s 2 /4R s .
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Lecture 12 figures 2 Fig. 12-5: A load resistor R L is connected to a network.
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Unformatted text preview: Fig. 12-6: We will reduce the network to its Thvenin equivalent by finding the linear relation between V AB and I L (Method III). Fig. 12-7: As we have shown before, the linear relation between I L and V AB is I L = V AB /R th + Vs/R th . Fig. 12-8: The Thvenin equivalent of the network in Fig. 12-6, with a load resistor R L attached. We set R L = R th to optimize the power absorbed. Lecture 12 figures 3 Fig. 12-10: The Thvenin equivalent of the network in Fig. 12-6. Fig. 12-9: We return to the network of Fig. 12-6, which we will reduce to its Thvenin equivalent by finding V oc and I sc (Method II)....
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This note was uploaded on 01/19/2012 for the course IE 230 taught by Professor Xangi during the Spring '08 term at Purdue University-West Lafayette.

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Lecture 12 - Fig. 12-6: We will reduce the network to its...

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