Lecture 17

Lecture 17 - The current is separated into the Zero-State...

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Lecture 17 figures 1 Fig. 17-1a: The source current turns on at t=0. Find the energy stored in the inductor of the circuit at t = (a) -10ms; (b) 20ms; and (c) 5 s. Fig. 17-1b: The current i L (t) for the circuit of Fig. 17-1a increases from -4 A to - 1.6 A with time constant τ = 20 ms. Fig. 17-1c: The current i L (t) for the circuit of Fig. 17-1a, with the 4A source doubled, increases from -4 A to +0.8A with time constant τ = 20 Fig. 17-2a: A voltage source drives a first-order network (in this case, an RL series combination). We want to find a solution for i(t) that is valid for a general V s (t).
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Lecture 17 figures 2 Fig. 17-2b: The solution i(t) for step function V s (t). Fig. 17-2c: From i(t), we can find V R (t) and V L (t). Fig. 17-3: The current i(t) that results when V s (t) changes from 1V for t<0 to 1V cos(ωt) for t>0.
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Unformatted text preview: The current is separated into the Zero-State and Zero-Input Responses. Fig. 17-3: The source voltage V s (t) that drives the circuit. Lecture 17 figures 3 Fig. 17-4: An R-L network driven by a source that produces a rectangular voltage pulse. Fig. 17-4c: The solution for the current i(t), valid for all t . Fig. 17-5: The voltage across the resistor resulting from a rectangular voltage pulse applied by the source. Find the two times at which V R = V s /2. Fig. 17-6: The voltage across the inductor resulting from a rectangular voltage pulse applied by the source. Lecture 17 figures 4 Fig. 17-7: The source voltage cycles between V s and 0. The period is 200 s, and the duty cycle is 50%. Fig. 17-7b: The voltage v R (t) waveform. After a few time constants, v R (t) repeats itself....
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Lecture 17 - The current is separated into the Zero-State...

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