TDEC121MTW06_Key

TDEC121MTW06_Key - TDEC 121 Winter 06 Midterm On the answer...

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TDEC 121 Winter 06 Midterm On the answer sheet (scantron) write your Name, Student ID Number, and Recitation Section Number. Choose the best (most correct) answer for each question AND ENTER IT ON YOUR ANSWER SHEET. 1. If a catalyst is added to a chemical reaction, the equilibrium yield of a product will be _______ , and the time taken to come to equilibrium will be before. a. higher; less than b. higher; the same as c. the same; less than d. lower; less than 2. Terms relating to certain types of substances conventionally do not appear in equilibrium constant expressions. These substances are a. pure solids and liquids. b. pure solids only. c. pure liquids only. d. pure solids, liquids and gases. 3. The equilibrium constant expression for the reverse of the reaction given below is 4 NH 3 (g) + 5 O 2 (g) 4 NO(g) + 6 H 2 O(g) a. K c = [NO] 4 [H 2 O] 6 [NH 3 ] 4 [O 2 ] 5 . b. K c 4[NO] 6[H 2 O] 4[NH 3 ] 5[O 2 ] . c. K c [NH 3 ] 4 [O 2 ] 5 [NO] 4 [H 2 O] 6 . d. K c 4[NH 3 ] 5[O 2 ] 4[NO] 6[H 2 O] . 4. If the equilibrium constants for the two reactions 2 HCl(g) H 2 (g) + Cl 2 (g) and I 2 (g) + Cl 2 (g) 2 ICl(g) are denoted K 1 and K 2 respectively, then the equilibrium constant for the reaction 2 HCl(g) + I 2 (g) 2 ICl(g) + H 2 (g) equals a. (K 1 /K 2 ) 2 . b. (K 1 K 2 ) 2 . c. K 1 K 2 . d. K 1 +K 2 . Page 1 of 4
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5. The equilibrium constant for the reaction NO(g) + 1/2 O 2 (g) NO 2 (g) has a value of K p = 1.23 at a certain temperature. What is the value of K p for the reaction 2 NO 2 (g)
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This note was uploaded on 01/17/2012 for the course BIO 141 taught by Professor Brown during the Spring '08 term at Drexel.

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TDEC121MTW06_Key - TDEC 121 Winter 06 Midterm On the answer...

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