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**Unformatted text preview: **x 1 and the average speed is (1/2) ( v 1 + v 2 ) = 17.5 s m , so the time needed to slow down is , s . 16 s m 5 . 17 m 80 m 360 =-and the total time is 24.0 s. c) The officer slows from 20 s m to 15 s m in 16.0 s (the time found in part (a)), so the acceleration is 0.31 2 s m . d), e)...

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