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Lab%2004%20%28-%29%20-%20Indirect%20Grav%20Det%20%28STUDENT%29

Lab%2004%20%28-%29%20-%20Indirect%20Grav%20Det%20%28STUDENT%29

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Indirect Gravimetric Determination Created by Jackie Jurchenko Created by Jackie Jurchenko
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Introduction Starting with an unknown mixture that contains 2  components - _________  (H 2 O trapped in crystal lattice)  and  ______ With heat, the ______ separates from the mixture  – then you can determine how much of each  ________ is present in your unknown.
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Calculations In order to find the amounts of each component need  to know how much _____ was lost. After  heating…. mass of sample and crucible _____ heating     – mass of sample and crucible _____ heating           = mass of water lost Then using __________ you can calculate the  amounts of the _____ and _____.
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con’t X g H 2 O x
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Unformatted text preview: x 244.3 g BaCl 2 . 2 H 2 O = 1 mol BaCl 2 . 2 H 2 O YY g BaCl 2 . 2 H 2 O (in sample) 1 mol BaCl 2 . 2 H 2 O = 2 mol H 2 O 1 mole H 2 O = 18.01 g H 2 O (lost) XX moles of water lost XX moles H 2 O x Y moles of BaCl 2 . 2 H 2 O Y mole of BaCl 2 . 2 H 2 O con’t Now you know mass of ½ of the sample – to find mass of NaCl: Original mass of sample- Y g BaCl 2 . 2 H 2 O Z g NaCl Then calculate % of each component: _g of ____________ x 100 = % of component g of _____________ Tips Pre-dry crucible. Once dried avoid touching with hands! (why?) Heat sample until at constant weight +/- 0.002g Cool slowly – don’t put on bench! Record Unknown Code! Show Calculations (accuracy counts) Solid waste in hood....
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