HW5 Solution (handwritten part)

# HW5 Solution (handwritten part) - Students’ Names Section...

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Unformatted text preview: Students’ Names Section # Section # EXERCISES 1. In a given project network, each activity has the same format (cells) as Activity 2' Earliest Start Time (ESE) Earliest Finish Time (EFTi) Duration 1‘,- Latest Start Time(LST,.) Latest Finish Time (LFTi) a. What is the project completion time? : a i i I 3 i . b; If activity D starts at time 8, will the project be delayed? yes. c. If activity E duration was reduced to 4, would the project completion time decrease? No. 247 250 4. Consider the project in the next page and answer the following questions. Activity’s time (in days) is given below the name in each activity’s box. a. What is the project completion time? 2 H A a 75 b. What is the duration of activity P? 6 dat a 5 c. What is the critical path? CWEWQQI d. What is the maximum amount of time activity G could be put on hold with— out delaying the project? ’7 (has (= 196) e. By what time could activity B start without delaying the project? ’7 f. Which of the following arcs, if removed, will reduce the project completion ~ time? Why? I. IK. CH) HI. III. DF. IV. AE. H] & .Eﬁzygxﬁgaga?_§vy 1 5 2 7. The following table describes the various activities of a new drug development in a pharmaceutical company. NORMAL CRASH NORMAL CRASH TIME (ti) TIME (ti’) COST (CI) COST(ci1 PREDECESSORS ACTIVITY A 4 2 50000 80000 # B 11 7 75000 85000 — C 9 6 90000 120000 A D 7 5 80000 120000 B E 12 8 125000 165000 B F 8 ‘76 85000 125000 C, D G 14 10 150000 200000 D, E H 16 l 11 180000 210000 C, E J a. Calculate the crash cost per week for each activity. 143 \$1519” 3: \$2,500 C: lit/0,000 pr20/000 5; {10,000 F: \$20,000 5: \$2,500 Hsf6/000 b. Formulate an LP program to crash this project to 30 weeks in the space below. Build a spreadsheet model of the project. Use Solver to ﬁnd the optimal solu~ tion. What is the minimum cost plan for crashing the project? pension, Vam‘atolts .' T1; -' Hm at which MAW-lg, 'i \$154478. (1.1;: amauut 0f Hm 0“:qu at— ac'h‘m't‘a. i._ m'm (5,000 CA + 2.500 C8 + (0,000 CC + 20,000 C], + [9,000 CE + 20,000 CF 4- (2,300 CcT + 6,000 CH 5-15. Tc 2 TA 'l' ‘l “ CA, TD 3T5 +ll~ C3, TE 3 TB 141-48, 7%;72+?_Cc TFZTp—rQ-CP, T4; TD +7~Cp Ts? T; +12- BE, THchf.q_ C}: l’ 254 Cos 3/ CDS 2, .2554, CF52, (4.5 q, C1155} all vau‘able; hpmmgaﬂve man—+1245] TF-c,_—.<22, TaquSté, TH‘CH 5w, CAsz, c350, ...
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