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Unformatted text preview: becomes F 166 = = = = = = = = ) ( 120 250 120 ) ( ) ( s 00858 . h 9 . 30 ft) F)(0.02778 Btu/lbm. 092 . )( lbm/ft (532 F . Btu/h.ft 42 s) 120 )( s 00858 . ( 113 21 t T e t T e T T T t T L C h V C hA b bt i c p p s ( b ) The total amount of heat transfer from a ball during a 2minute period is Btu 97 . 9 F ) 166 250 ( F) Btu/lbm. 092 . )( lbm 29 . 1 ( )] ( [ lbm 290 . 1 6 ft) 12 / 2 ( ) lbm/ft 532 ( 6 3 3 3 = = = = = = = t T T mC Q D V m i p Then the rate of heat transfer from the balls to the water becomes Btu/min 1196 = = = ) Btu 97 . 9 ( balls/min) 120 ( ball ball Q n Q total & & Therefore, heat must be removed from the water at a rate of 1196 Btu/min in order to keep its temperature constant at 120 . F 44...
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This note was uploaded on 01/19/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.
 Fall '10
 Dr.DanielArenas
 Thermodynamics, Mass, Heat

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