Unformatted text preview: becomes F 152 ° = ⎯→ ⎯ = − − ⎯→ ⎯ = − − = = ° ° = = = − − ∞ ∞ ) ( 120 250 120 ) ( ) ( s 01157 . h 66 . 41 ft) F)(0.02778 Btu/lbm. 216 . )( lbm/ft (168 F . Btu/h.ft 42 s) 120 )( s 01157 . ( 113 21 t T e t T e T T T t T L C h V C hA b bt i c p p s ρρ ( b ) The total amount of heat transfer from a ball during a 2minute period is Btu 62 . 8 F ) 152 250 ( F) Btu/lbm. 216 . )( lbm 4072 . ( )] ( [ lbm 4072 . 6 ft) 12 / 2 ( ) lbm/ft 168 ( 6 3 3 3 = ° − ° = − = = = = = t T T mC Q D V m i p Then the rate of heat transfer from the balls to the water becomes Btu/min 1034 = × = = ) Btu 62 . 8 ( balls/min) 120 ( ball ball Q n Q total & & Therefore, heat must be removed from the water at a rate of 1034 Btu/min in order to keep its temperature constant at 120 . ° F 45...
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This note was uploaded on 01/19/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.
 Fall '10
 Dr.DanielArenas
 Thermodynamics, Mass, Heat

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