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Thermodynamics HW Solutions 313

# Thermodynamics HW Solutions 313 - L=1"[m 1 m length of...

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Chapter 4 Transient Heat Conduction 4-39 "!PROBLEM 4-39" "GIVEN" r_o=0.35/2 "[m]" T_i=400 "[C]" T_infinity=150 "[C]" h=60 "[W/m^2-C]" "time=20 [min], parameter to be varied" "PROPERTIES" k=14.9 "[W/m-C]" rho=7900 "[kg/m^3]" C_p=477 "[J/kg-C]" alpha=3.95E-6 "[m^2/s]" "ANALYSIS" Bi=(h*r_o)/k "From Table 4-1 corresponding to this Bi number, we read" lambda_1=1.0935 A_1=1.1558 J_1=0.4709 "From Table 4-2, corresponding to lambda_1" tau=(alpha*time*Convert(min, s))/r_o^2 (T_o-T_infinity)/(T_i-T_infinity)=A_1*exp(-lambda_1^2*tau)
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Unformatted text preview: L=1 "[m], 1 m length of the cylinder is considered" V=pi*r_o^2*L m=rho*V Q_max=m*C_p*(T_i-T_infinity)*Convert(J, kJ) Q/Q_max=1-2*(T_o-T_infinity)/(T_i-T_infinity)*J_1/lambda_1 time [min] T o [C] Q [kJ] 5 425.9 4491 10 413.4 8386 15 401.5 12105 20 390.1 15656 25 379.3 19046 30 368.9 22283 35 359 25374 40 349.6 28325 45 340.5 31142 50 331.9 33832 55 323.7 36401 60 315.8 38853 4-24...
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