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Unformatted text preview: t h k hx t x erfc T T T t x T i i 2 exp 2 ) , ( 2 2 where L =0.3 m Wood Slab T i = 25 C Hot gases T = 550 C x 0 628 . 1 276 . 1 276 . 1 C W/m. 0.17 ) s 60 5 )( s / m 10 (1.28 C) . W/m 35 ( 2 2 2 2 27 2 = = = = = k t h k t h k t h Noting that x = 0 at the surface and using Table 43 for erfc values, 630 . ) 0727 . )( 0937 . 5 ( 1 ) 276 . 1 ( ) 628 . 1 exp( ) ( 25 550 25 ) , ( = = + + = erfc erfc t x T Solving for T ( x, t ) gives C 356 = ) , ( t x T which is less than the ignition temperature of 450 C. Therefore, the wood will not ignite. 453...
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This note was uploaded on 01/19/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.
 Fall '10
 Dr.DanielArenas
 Thermodynamics, Convection, Mass, Heat

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