Thermodynamics HW Solutions 352

Thermodynamics HW - Chapter 4 Transient Heat Conduction = t L2 = o,wall = = t ro 2 o,cyl =(0.0077 ft 2 h(10 60 h(2.5 12 ft 2 = 0.03 < 0.2(Be

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Chapter 4 Transient Heat Conduction τ α == = < t L 2 00077 25 12 003 02 (. (./ . ft / h)(10 / 60 h) ft) 2 2 . (Be cautious!) 1 ) 2728 . 1 ( ) 03 . 0 ( ) 5421 . 1 ( 1 0 , 2 2 1 = = = e e A T T T T i wall o τλ θ = > t r o 2 0 0077 04 12 1156 0 2 (. / .. ft / h)(10 / 60 h) ft) 2 2 θ λτ o cyl i TT Ae e , )(. ) ) . = = −− 0 1 2 1589 1156 1 2 2 15618 0 007 F 211 ° = ⎯→ = = × = × = ) , 0 , 0 ( 007 . 0 212 40 212 ) , 0 , 0 ( 007 . 0 007 . 0 1 ) , 0 , 0 ( , , cylinder short t T t T T T T t T cyl o wall o i θθ After 15 minutes = < t L 2 0 0077 0 045 0 2 . ft / h)(15/ 60 h) ft) 2 2 . (Be cautious!) 1 ) 2728 . 1 ( ) 045 . 0 ( ) 5421 . 1 ( 1 0 , 2 2 1 = = = e e A T T T T i wall o = > t r o 2 0 0077 1734 02 ft / h)(15/ 60 h) ft) 2 2 θ o cyl i e , )(. ) ) . = = 0 1 2 1589 1 734 1 2 2 15618 0 0005 F 212 ° = = = × = × = ) , 0 , 0 ( 0005 . 0 212 40
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This note was uploaded on 01/19/2012 for the course PHY 4803 taught by Professor Dr.danielarenas during the Fall '10 term at UNF.

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