exam 2 problems - 0.200 M Pb(NO 3 2 is reacted with 150.0...

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1. Write the molecular, total ionic, and net ionic equations for the following reactions: a) Li 3 P (aq) + Ca(ClO 2 ) 2 (aq) b) H 2 S (aq) + Fe(NO 3 ) 3 (aq) 2. One way to analyze the amount of vitamin C, C 6 H 8 O 6, in a sample is to titrate it with dichromate. Balance this redox reaction, which takes place in acidic solution: Cr 2 O 7 2-(aq) + C 6 H 8 O 6 (aq) C 6 H 8 O 7 (aq) + Cr 3+( aq) in acidic solution. What was reduced? What was oxidized? Oxidizing agent? Reducing agent? What is the oxidation state of carbon in vitamin C? _______ of Cr in Cr 2 O 7 2- ? ______ How many electrons are transferred in this reaction? 3. 20.0 mL of a 2.0M sodium chloride solution is diluted to a volume of 60.0 mL It’s new concentration is __________. 4. Draw a pictures of a) MgCl 2 (aq) b) HNO 3 (aq) and c) HF(aq) 5. The products of the reaction of sodium carbonate and hydrochloric acid are: The products of the reaction of ammonium chloride and potassium hydroxide: 6. What mass of solid lead (II) chloride can be produced when 50.0 mL of
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Unformatted text preview: 0.200 M Pb(NO 3 ) 2 is reacted with 150.0 mL of HCl(g) at 755 torr and 35 o C? 7 . Calculate the mole fraction and the molarity of glucose (C 6 H 12 O 6 ) in an aqueous glucose solution that is 2.3 m. The density of this solution is 1.007 g/mL. 8. 0.250 g of a binary unknown acid, HX, requires 31.96 mL of a 0.09668M NaOH solution when titrated. What is the identity of the unknown acid? 9. A 1.00 g sample of a metal X (that is known to form X 2+ ions) was added to 0.100 liters of 0.500 M H2SO4. After all the metal had reacted, the remaining acid required 0.0334 liters of 0.500 M NaOH solution for neutralization. Calculate the molar mass of the metal . 10. The following redox reaction takes place in basic solution. AlO 2-( aq ) + PO 3 3- ( aq ) HPO 4 2-( aq ) + Al (s) How many g of a 0.45% NaAlO 2 solution would be required to titrate 3.0 mL of 0.10M sodium phosphite? Answers: 6) 0.819g 7) 0.040; 1.6M 8) HBr 9) 24 g/mol 10) 4.7 g...
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