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Unformatted text preview: In a constant volume process: w = 0 (because this is a constant volume process) q v = E = nC v T = 3000 J = E = (2.00 mol)(12.47 J.K1 mol1 ) T T = 3000 J/(2.00mol)(12.47 J K1 mol1 ) = 120 K T final = 298 K + 120 K = 418 K H = nC p T = (2.00 mol)(20.79 J.K1 mol1 ) 120 K = 4.99 kJ In a constant pressure process: q p = H = nC p T = 3000 J = H = (2.00 mol)(20.79 J.K1 mol1 ) T T = 3000 J/(2.00mol)(20.79 J K1 mol1 ) = 72.2 K T final = 298 K + 72.2 K = 370 K p V = nR T w = p V = (2.00 mol)(8.314 J.K1 mol1 )72.2 K = 1.20 kJ E = nC v T = (2.00 mol)(12.47 J.K1 mol1 ) 72.2 K = 1.80 kJ...
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This note was uploaded on 01/18/2012 for the course CHEM 152B taught by Professor Zhang during the Winter '12 term at University of Washington.
 Winter '12
 zhang
 Chemistry

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