Ch 4_AcidBaseLR_102511

# Ch 4_AcidBaseLR_102511 - Let’s focus on net ionic eqn...

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10/25/2011 1 Acid/Base and Limiting Reagent 75.0 mL of 0.250 M HCl is added to 225.0 mL of 0.0550 M Ba(OH) 2 solution. What is the concentration of the excess H + or OH - ions left in this solution? 2 HCl(aq) + Ba(OH) 2 (aq) 2 H 2 O(l) + BaCl 2 (aq) 1. How many moles of each reactant? 2. Which is limiting? 3. How much H + or OH - is left over? 4. What is the new volume? 5. What is the concentration of the excess reactant? 75.0 mL 0.250 M 225.0 mL 0.0550 M Acid/Base and Limiting Reagent 2 HCl(aq) + Ba(OH) 2 (aq) 2 H 2 O(l) + BaCl 2 (aq) 0.018750 moles 0.012375 moles 1. How many moles of each reactant?
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Unformatted text preview: Let’s focus on net ionic eqn. 0.01875 moles H + 2(0.012375 moles) = 0.02475 moles OH- 2. Which is limiting? 2:1 ratio…0.01875 moles H + require 0.009375 moles OH- (H + is LR) 3. How much H + or OH-is left over? 0.02475 moles OH-less 0.009375 moles used, so 0.015375 moles OH-left 4. What is the new volume? 0.0750 L plus 0.225 L = 0.300 L 5. What is the concentration of the excess reactant? 0.015375 moles OH- / 0.300 L = 0.05125 = 0.0513 M OH- The concentration for Ba(OH) 2 would be 0.0256 M. 0.0750 L * 0.250 M 0.225 L * 0.0550 M...
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