Unformatted text preview: alternatively, work it out by considering the following relation âˆž X n,p,k =0 I nkp s n n ! t k k ! (2 Î» ) p p ! = âˆš Ï€e Î» 2 +2( st + Î»s + Î»t ) , where I nkp is the following useful integral I nkp = Z âˆžâˆž H n ( z ) H k ( z ) ez 2 z p dz for n,k,p nonnegative integers. This latter sum may be used to compute I nkp by comparing equal powers of s n t k Î» p ....
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 Fall '11
 DavidJ.Masiello
 Chemistry, Addition, ez dz, Inkp, relation sn tk

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