asst2-f10-solns

# asst2-f10-solns - MATH 137 Solutions to Assignment#2 Part...

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2. (a) In order for x to be in the domain of f , we must have x 2 + 1 0, which is true for all x , and we also must have that x + x 2 + 1 > 0 in order for ln to be deﬁned. Notice that x 2 + 1 > x 2 0 for all x R . Therefore, x 2 + 1 > x 2 = | x | , since the square root function is strictly increasing on its domain. So we have that
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## This note was uploaded on 01/18/2012 for the course MATH 137 taught by Professor Speziale during the Fall '08 term at Waterloo.

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asst2-f10-solns - MATH 137 Solutions to Assignment#2 Part...

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