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Unformatted text preview: d G ( ) S S d E G G G . 10 3 y 6 x 9 4 1 b. Find the voltage in the loop again using the closed path integral l d E G G by explicitly selecting the integration direction to match your S d G direction in part a. (use the right hand rule). C. In the figure below fill in the polarity on the imaginary source of voltage, draw in the direction of the resulting current flow and calculate the current value. 10 V 3 y x 9 6 4 2...
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- Fall '10