Control Charts

Control Charts - Control Charts for Attributes: An Example...

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1 Hometown Bank Control Charts for Attributes: An Example
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2 Example 7.3 Hometown Bank UCL p = p + z σ p LCL p = p - z σ p σ p = p (1 - p ) / n 1 15 2 12 3 19 4 2 5 19 6 4 7 24 8 7 9 10 10 17 11 15 12 3 Total 147 Total defectives Total observations p = n = 2500 Control Charts
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3 Hometown Bank UCL p = p + z σ p LCL p = p - z σ p σ p = p (1 - p ) / n Account Number 2 12 3 19 4 2 5 19 6 4 7 24 8 7 9 10 10 17 11 15 12 3 Total 147 147 12(2500) p = n = 2500 Control Charts
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4 Hometown Bank UCL p = p + z σ p LCL p = p - z σ p σ p = p (1 - p ) / n Account Number 2 12 3 19 4 2 5 19 6 4 7 24 8 7 9 10 10 17 11 15 12 3 Total 147 p = 0.0049 n = 2500 Control Charts
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5 Hometown Bank UCL p = p + z σ p LCL p = p - z σ p σ p = p (1 - p ) / n Proportion Account Number Defective 0.006 2 12 0.0048 3 19 0.0076 4 2 0.0008 5 19 0.0076 6 4 0.0016 7 24 0.0096 8 7 0.0028 9 10 0.004 10 17 0.0068 11 15 0.006 12 3 0.0012 Total 147 p = 0.0049 n = 2500 Control Charts
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6 UCL p = p + z σ p LCL p = p z p p = p (1 – p ) / n n = 2500 p = 0.0049 Control Charts for Attributes Hometown Bank
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7 UCL p = p + z σ p LCL p = p z p p = 0.0049(1 – 0.0049)/2500 n
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This note was uploaded on 01/20/2012 for the course MGT 3200 taught by Professor Moodie during the Spring '08 term at Kennesaw.

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Control Charts - Control Charts for Attributes: An Example...

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