Homework3_solution

Homework3_solution - - n p p and solve for n . The sample...

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Homework 3 Due next Thursday (2/10/2010) #1 A soft-drink manufacturer purchases aluminum cans from an outside vendor. A random sample of 70 cans is selected from a large shipment, and each is tested for strength by applying an increasing load to the side of the can until it punctures. Of the 70 cans, 52 meet the specification for puncture resistance. (a) Find a 95% confidence interval for the proportion of cans in the shipment that meet the specification. Use formula - + - - , 1 96 . 1 , 1 96 . 1 n p p p n p p p [0.6405, 0.8452] (b) Find the sample size needed for a 95% confidence interval to specify the proportion to within ± 0.05. Set 05 . 0 1 96 . 1 =
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Unformatted text preview: - n p p and solve for n . The sample size should be at least 293.5394 294. #4: Test the hypothesis that the average content of containers of a particular lubricant is 10 liters if the contents of a random sample of 10 containers are 10.2, 9.7, 10.1, 10.3, 10.1, 9.8, 9.9, 10.4, 10.3, and 9.8 liters. Assume that the distribution of contents is normal (a) Set up the null and alternative hypotheses and use a 0.01 level of significance; (b) Find the P_value, using EXCEL or Minitab. Refer to your lecture notes. #5: Exercise 17.2 (only required for students from IEN/MAS 311. Please let me know if you need any extra time. )...
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Homework3_solution - - n p p and solve for n . The sample...

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