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Homework7_solution - Homework 7 Due next Thursday#1...

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Homework 7 Due next Thursday (3/29/2011) #1: Exercise 12.2 and Exercise 12.17 The regression equation is y = - 3.37 + 0.00362 x1 + 0.948 x2 Predictor Coef SE Coef T P Constant -3.3727 0.6360 -5.30 0.000 x1 0.0036167 0.0006121 5.91 0.000 x2 0.9476 0.3609 2.63 0.028 S = 0.406301 R-Sq = 82.3% R-Sq(adj) = 78.3% Analysis of Variance Source DF SS MS F P Regression 2 6.9008 3.4504 20.90 0.000 Residual Error 9 1.4857 0.1651 Total 11 8.3865 1651 . 0 2 = σ 1.0 0.5 0.0 -0.5 -1.0 99 95 90 80 70 60 50 40 30 20 10 5 1 Residual Percent Normal Probability Plot (response is y) 2.5 2.0 1.5 1.0 0.5 0.0 -0.5 0.75 0.50 0.25 0.00 -0.25 -0.50 Fitted Value Residual Versus Fits (response is y) The data points in the normal probability plot approximately lie on the one line, but the residuals seem to have a quadratic relationship with the fitted values. After we add one additional random variable, x1*x2 and take off x1, the residuals look more random.
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3.0 2.5 2.0 1.5 1.0 0.5 0.0 0.4 0.3 0.2 0.1 0.0 -0.1 -0.2 -0.3 Fitted Value Residual Versus Fits (response is y) #2: Exercise 12.45 The Minitab output for the estimated equation: The regression equation is MPG = 5.96 - 0.000038 Odometer + 0.337 Octane - 12.6 z2 - 13.0 z3 Predictor Coef SE Coef T P Constant 5.959 7.058 0.84 0.408 Odometer -0.00003773 0.00001593 -2.37 0.028 Octane 0.33735
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