SG3 - 2 x= 15 therefore, sin(arcos 1/4) = 15 7.7 [34] cot-1...

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7.1 [28] cscsec/cot = 1/sin * 1/cos * sin/cos = 1/cos 2 7.4 [62] sin9x - sin3x = 2cos [(9x+3x/2)]sin[(9x+3x/2)] = 2cos6xsin3x 7.5 [78] sin (arccos 1/4) 4 2 =1 2 +X
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Unformatted text preview: 2 x= 15 therefore, sin(arcos 1/4) = 15 7.7 [34] cot-1 x = tan-1 (4/3), therefore tanx=4/3 cot-1 x = u , x=cotu u=3/4 solution set ={3/4}...
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This note was uploaded on 01/18/2012 for the course MATH 129 taught by Professor Nilanjanpaul during the Spring '11 term at Thomas Edison State.

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