# WA6 - Robert Edwin Goode Student ID: 0451848 Mentor:...

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Robert Edwin Goode Student ID: 0451848 Mentor: Nilajan Paul Date: 11/17/11 Writing Assignment #6 Section 10.1[10,22,28,34,38,40] 10. -1/2x = (y+3) 2 Domain: [0,-∞) Range: (-∞, 0) 22. -9y=X 2 Has the form X 2 =4py, so 4p=-9 P=-9/4 Focus = (0,-9/4) Directrix, y=-p, is y=9/4. The vertex is (0,0), and the axis of the parabola is the y-axis 28. (X+2) 2 =20y (X-(-2)) 2 =20(y-0) H=-2, k=0 4p=20 So p=5. The vertex is (-2,0), focus is (-2,5), directrix is y=-5, equation of the axis is x=-2 34.

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Focus (-1/2,0) Vertex at the origin Equation has the form y 2 =4px. Since p=-1/2 it opens to the left Y 2 =4(-1/2)x Y 2 =-2x 38. Has the form X 2 =4py 2 2 =4p(-4) P=-1/4 X 2 =-1/4y 40. Vertex = (-2,1), focus (-2,-3) Distance between the focus and vertex = abs (-3-1) = 4 Since parabola opens downward choose p=-4 H=-2 and k=1 (X+2) 2 =4(-4)(y-1) (X+2) 2 =-16(y-1) Section 10.2 (2,4,20,22,32) 2. a. Ellipse b. Ellipse c. Parabolic d. Line 4. X 2 /16 +Y 2 /25 = 1
The graph is an ellipse with center (0,0) Since 5>4 a=5 and b=4. The major axis is horizontal. Thus the vertices are (0,5) and (0,-5). The endpoints of the minor axis are (4,0), (-4,0). The domain is [-4,4] and the range is [-5,5]

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## WA6 - Robert Edwin Goode Student ID: 0451848 Mentor:...

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