Chips Ahoy Challenge

Chips Ahoy Challenge - that no outliers exist d Is it reasonable to use the one-mean t-interval procedure to obtain a confidence interval for the

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Robert E Goode Thomas Edison State College STA-201-OL010 Mentor: Steve Stutz Date: 10/04/11 Chips Ahoy Challenge a. Obtain and interpret a point estimate for the mean number of chocolate chips per bag for all bags of Chips Ahoy! Cookies. ( Note: The sum of the data is 52,986.) n = 42 and Sum X i (1<i<n) = 52986 Mean X = Sum X i /n = 52986/42 = 1261.57 1261.57 represents the mean number of chocolate chips per bag of Chips Ahoy Cookies. b. Construct and interpret a normal probability plot, boxplot, and histogram of the data. Normal Probability Plot

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The number of chocolate chips per bag for 42 bags is normally distributed. Box Plot Data is right skewed, median is around 1230.
Histogram Histogram shows that the data is right skewed. c. Use the graphs in part (b) to identify outliers, if any. The Boxplot indicates potential outliers, but after review of the other two graphs it is concluded

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Unformatted text preview: that no outliers exist. d. Is it reasonable to use the one-mean t-interval procedure to obtain a confidence interval for the mean number of chocolate chips per bag for all bags of Chips Ahoy! Cookies? Explain your answer. Yes, due to the fact that the sample size is large enough (42). e. Determine a 95% confidence interval for the mean number of chips per bag for all bags of Chips Ahoy! Cookies, and interpret your result in words. ( Note: 1261.6; s = 117.6.) = 117.6 mean = 1261.6 x = /n = 117.6/42 = 18.146 mean -2 x = 1261.6 - 36.292 = 1225.308 mean +2 x = 1261.6 +36.292 = 1297.892 therefore, confidence interval is 1225.308 1297.892 With 95.44% confidence we can say that the amount of chocolate chips in a bag of Chips Ahoy! Cookies is between the 1225.308 1297.892...
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This note was uploaded on 01/18/2012 for the course STA 201 taught by Professor Kohn during the Winter '09 term at Thomas Edison State.

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Chips Ahoy Challenge - that no outliers exist d Is it reasonable to use the one-mean t-interval procedure to obtain a confidence interval for the

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