WA7 - Robert E Goode Thomas Edison State College...

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Robert E Goode Thomas Edison State College STA-201-OL010 Mentor: Steve Stutz Date: 11/08/11 Writing Assignment #7 Exercises 10.1 (10.10 and 10.16) 10.10 a. Amount spent. b. Teens, u1 and adults (u2) H 0 : u1=u2 H a : u1<u2 c. Left tailed. 10.16 U1 = 7.9 and ơ 1 = 5.4 U 2 = 7.1, ơ 2 = 4.6 a. mean = 7.9 -7.1 =.8 = √(79.48/6) = 3.64 ơ b. No, mean does not change across different populations c. No, the sample size are too small and it is unknown if they are normally distributed Exercises 10.2 (10.24, 10.30, 10.34, 10.40)
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10.24 Unreasonable because sample is not large enough and population standard deviations are not equal. 10.30 a. H 0 : u1=u2 H a : u1<u2 α = 0.05 S = √(n-1)s 2 +(n-1)s 2 /(n 1 +n 2 )-2 =√(21.4783) = 4.6 T = mean1 – mean2/(S√(1/n + 1/n) = -1.59 Df = 10+15-2 = 23 T=1.71 -1.59>1.71 90% confidence interval = X1-X2+t*S√(1/n +1/n) = -6.24 - .24 10.34 P1: male, n=30, x=37.1 and s=38.5 P2: female, n=30, x=55.8 and s=48.3 α = 0.01 S = √((n-1)S +(n-1)S)/(n1+n2 -2) = 43.68 T = x1-x2/S(√(1/n1)+(1/n2)) = 1.61 df = 10+15-2 = 58 t = -2.390 -1.6139 > -2.390 @ 1 percent significance the data is inconclusive. 10.40 98% confidence: X1-x2 +t*S*(√(1/n1)+(1/n2)) = -45.15 – 8.75
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Exercises 10.3 (10.64, 10.70) 10.64 P1: n=51, x1=115.1 and s1=79.4 P2: n2=19, x2=24.3 and s2=10.5 α = 0.01 t = 7.98159 df = 49 critical value = 2.403 7.98159 > 2.403,
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